Suppose gcd(a, n) = 1. Show that there exists b such that [a]n * [b]n = [1]n.


Suppose gcd(a, n) = 1. Show that there exists b such that [a]n * [b]n = [1]n.

Suppose gcd(a, n) = 1. Show that there exists b such that [a]n * [b]n = [1]n.


Suppose gcd(a, n) = 1. Show that there exists b such that [a]n * [b]n = [1]n.

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